use already calculated one.LowestCost

day-16/internal/one/solve.go

@@ -4,6 +4,8 @@ import (
 	"bytes"
 )
 
+var LowestCost int
+
 func Solve(buf []byte) (int, error) {
 	r := bytes.NewReader(buf)
 	graph, err := parseLines(r)
@@ -11,10 +13,10 @@ func Solve(buf []byte) (int, error) {
 		return 0, err
 	}
 
-	lowestCost, err := graph.dijkstra()
+	LowestCost, err = graph.dijkstra()
 	if err != nil {
 		return 0, err
 	}
 
-	return lowestCost, nil
+	return LowestCost, nil
 }

day-16/internal/two/graph.go

@@ -2,10 +2,10 @@ package two
 
 import (
 	hp "container/heap"
-	"math"
 	"slices"
 	"strings"
 
+	"github.com/onyx-and-iris/aoc2024/day-16/internal/one"
 	log "github.com/sirupsen/logrus"
 )
 
@@ -32,20 +32,18 @@ func (g *graph) dijkstra() int {
 	hp.Push(heap, move{g.start, 0, []node{g.start}})
 	visited := make(map[node]int)
 	const turnCost int = 1000
-	lowestCost := math.MaxInt
 
-	bestPaths := [][]node{}
+	lowestCostPaths := [][]node{}
 	for heap.Len() > 0 {
 		current := hp.Pop(heap).(move)
 
 		// we're on a path that's already exceeded the lowest cost
-		if current.cost > lowestCost {
+		if current.cost > one.LowestCost {
 			continue
 		}
 
 		if g.valueAt(current.node) == 'E' {
-			bestPaths = append(bestPaths, current.path)
-			lowestCost = current.cost
+			lowestCostPaths = append(lowestCostPaths, current.path)
 			continue
 		}
 
@@ -71,7 +69,7 @@ func (g *graph) dijkstra() int {
 	}
 
 	possibleSafe := make(map[coords]struct{})
-	for _, path := range bestPaths {
+	for _, path := range lowestCostPaths {
 		for _, n := range path {
 			possibleSafe[n.coords] = struct{}{}
 		}